#include<iostream.h>
#include<conio.h>
void main()
{
clrscr();
long int num,r=0;
cout<<"Enter an integer:\t";
cin>>num;
while(num>0)
{
r=r*10;
r=r+num%10;
num=num/10;
}
cout<<"\nThe Revers of the number is "<<r<<endl;
getch();
}
Explanation of the program
Two variables are declared one is for the number which is to be reversed and that will be defined by the user as an input and the other is r in which we will store the reverse of the number.
Now the main task is happening in the loop, while loop is used in this program.
Suppose we entered 123
Now num = 123
The expression of while loop is true (123 is greater than 0); the control will come inside the loop and will execute the following statement
r is initialized by 0 at the starting of the program, so we have the values
Now calculate what will happen Two variables are declared one is for the number which is to be reversed and that will be defined by the user as an input and the other is r in which we will store the reverse of the number.
Now the main task is happening in the loop, while loop is used in this program.
Suppose we entered 123
Now num = 123
The expression of while loop is true (123 is greater than 0); the control will come inside the loop and will execute the following statement
{
r=r*10;
r=r+num%10;
num=num/10;
}
Now dry run it in your mind. r is initialized by 0 at the starting of the program, so we have the values
r = 0;
num = 123;
the value of r become 0 in first line.
Then it will become 3
r = 0 + 123 % 10;
r = 0 + 3;
r = 3
Now in the last statement num will become 12num = 123 / 10;
num = 12
Because we have taken the data type as int so it will not take the decimal value. Now all the statements has executed so the loop will again check its expression which is again true (12 is greater than 0), so the control will again come inside the loop and will execute the statements with updated values, this process will continue until the expression in while don't become false and at last it will print the reversed value as the output.
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